Column Wise Traversal
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Column Wise Traversal
Input :
A = [ [1, 2, 3], [4, 5, 6] ]
Output :
1 4 2 5 3 6
Explanation:
For the given matrix, the first column is [1, 4], the second is [2, 5] and the third is [3, 6].
For column-wise traversal, you must traverse the first column, the second column, and then the third.
First-line contains 'T,' denoting the number of Test cases.
For each Test case:
The first line contains two integers, ‘N' and ‘M’.
The following ‘N’ lines have ‘M’ integers each, denoting the matrix ‘A’.
You must return the array with elements in order of column-wise traversal.
You don’t need to print anything. Just implement the given function.
1 <= T <= 10
1 <= N * M <= 10^5
1 <= A[ i ][ j ] <= 10^9
Time Limit: 1 sec
2
2 2
4 3
2 1
5 1
1
2
3
4
5
4 2 3 1
1 2 3 4 5
For test case one:
Input :
A = [ [4, 3], [2, 1] ]
Output :
4 2 3 1
Explanation: For the given matrix, the first column is [4, 2], and the second is [3, 1].
For column-wise traversal, you need to traverse the first column and then the second column.
For test case two:
Input :
A = [ [ 1 ], [ 2 ], [ 3 ], [ 4 ], [ 5 ] ]
Output :
1 2 3 4 5
Explanation: For the given matrix, the first column is [1, 2, 3, 4, 5].
For column-wise traversal, you need to traverse the first column.
2
1 1
4
1 5
1 2 3 4 5
4
1 2 3 4 5
code for this
public class Solution { public static int[] printColWise(int[][] a) { int numRows = a.length; int numCols = a[0].length; int[] result = new int[numRows * numCols]; int index = 0;
for (int j = 0; j < numCols; j++) { for (int i = 0; i < numRows; i++) { result[index++] = a[i][j]; } }
return result; }
public static void main(String[] args) { // Sample input int[][] matrix1 = {{4, 3}, {2, 1}}; int[][] matrix2 = {{1}, {2}, {3}, {4}, {5}};
// Call the printColWise function for each test case int[] result1 = printColWise(matrix1); int[] result2 = printColWise(matrix2);
// Print the results for (int num : result1) { System.out.print(num + " "); } System.out.println();
for (int num : result2) { System.out.print(num + " "); } }}
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